# Ballistic pendulum

1. Nov 1, 2005

### lando45

How do I go about solving this problem? No diagram is given, so it's a little hard-to-picture in my head, so I drew a basic diagram but it hasn't really helped.

I use a ballistic pendulum. Large block of wood has a mass M2 = 3.000 kg, and the bullet has a mass of m1 = 25 g. In this problem the bullet completely penetrates the wood and emerges with a speed of vf = 40.0 m/s. The wood, as part of a pendulum, swings up to a maximum height of h = 4.0 cm.

Determine the speed of the block of wood after the bullet has passed through it, and the initial speed of the bullet.

Much thanks

2. Nov 1, 2005

### Chi Meson

Conservation of mechanical energy (PE and KE) tells you how fast the block was going after the collision.

Conservation of momnetum tells you how fast the bullet was going before the collision.

3. Nov 1, 2005

### lando45

So I should be using ½mv² and mgh? The mass of what though? The bullet or the block of wood? Or both? Also, what does the question mean when it says: "with a speed of vf = 40.0 m/s" - what is vf?

4. Nov 1, 2005

### lando45

OK, I worked out the Kinetic Energy of the bullet, having passed through the block, using ½mv², and I got a value of 20J, having converted everything into m and kg. Then I calculated the Potential Energy of the block, using mgh, and I got 1.1172J, but I don't see how this helps me...I thought I need to use theta and sine/cosine to answer this? Or is it all to do with energy? Thanks

5. Nov 1, 2005

### NateTG

The ballistic pendulum stuff generally works this way:
There is a perfectly inelastic collision between the bullet and the target, and then the swing up has conserved energy.

6. Nov 1, 2005

### Chi Meson

OK, you got PE. This is PE at the top. What kind of energy was it at the bottom?

7. Nov 2, 2005

### lando45

Kinetic energy?

8. Nov 2, 2005

### Chi Meson

yes. what is the formula for KE. Can you fid the speed of the block at the bottom (right after the collision with the bullet)?