Ballistic Pendulum Problem: Solving for Bullet and Block Speeds

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Homework Help Overview

The discussion revolves around a ballistic pendulum problem involving a bullet and a block of wood. The original poster describes the setup, including the masses of the bullet and block, the bullet's speed after passing through the block, and the maximum height the block reaches after the collision. The goal is to determine the speed of the block after the bullet passes through and the initial speed of the bullet.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of conservation of mechanical energy and momentum to solve the problem. There are questions about which mass to use in energy calculations and clarifications sought regarding the meaning of the given speed of the bullet after it exits the block.

Discussion Status

Some participants have provided insights into using kinetic and potential energy formulas, while others are exploring the relationship between energy before and after the collision. There is an ongoing exploration of how to apply these concepts effectively, with no clear consensus yet on the approach.

Contextual Notes

Participants note the absence of a diagram and express difficulty in visualizing the problem. There is also mention of potential confusion regarding the energy types involved and the specifics of the calculations needed.

lando45
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How do I go about solving this problem? No diagram is given, so it's a little hard-to-picture in my head, so I drew a basic diagram but it hasn't really helped.

I use a ballistic pendulum. Large block of wood has a mass M2 = 3.000 kg, and the bullet has a mass of m1 = 25 g. In this problem the bullet completely penetrates the wood and emerges with a speed of vf = 40.0 m/s. The wood, as part of a pendulum, swings up to a maximum height of h = 4.0 cm.

Determine the speed of the block of wood after the bullet has passed through it, and the initial speed of the bullet.


Much thanks
 
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Conservation of mechanical energy (PE and KE) tells you how fast the block was going after the collision.

Conservation of momnetum tells you how fast the bullet was going before the collision.
 
So I should be using ½mv² and mgh? The mass of what though? The bullet or the block of wood? Or both? Also, what does the question mean when it says: "with a speed of vf = 40.0 m/s" - what is vf?
 
OK, I worked out the Kinetic Energy of the bullet, having passed through the block, using ½mv², and I got a value of 20J, having converted everything into m and kg. Then I calculated the Potential Energy of the block, using mgh, and I got 1.1172J, but I don't see how this helps me...I thought I need to use theta and sine/cosine to answer this? Or is it all to do with energy? Thanks
 
The ballistic pendulum stuff generally works this way:
There is a perfectly inelastic collision between the bullet and the target, and then the swing up has conserved energy.
 
lando45 said:
OK, I worked out the Kinetic Energy of the bullet, having passed through the block, using ½mv², and I got a value of 20J, having converted everything into m and kg. Then I calculated the Potential Energy of the block, using mgh, and I got 1.1172J, but I don't see how this helps me...I thought I need to use theta and sine/cosine to answer this? Or is it all to do with energy? Thanks

OK, you got PE. This is PE at the top. What kind of energy was it at the bottom?
 
Chi Meson said:
OK, you got PE. This is PE at the top. What kind of energy was it at the bottom?

Kinetic energy?
 
yes. what is the formula for KE. Can you fid the speed of the block at the bottom (right after the collision with the bullet)?
 

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