Banked Curves in involving frictions

  • Thread starter Thread starter Addie
  • Start date Start date
  • Tags Tags
    Curves
AI Thread Summary
A car traveling in a circle with a radius of 50 meters and a banking angle of 30 degrees has a coefficient of static friction of 0.3. The maximum velocity for this scenario is calculated to be 22.8 m/s using the equation derived from the forces acting on the car. To find the apparent weight, which is equal to the normal force, one must analyze the vertical forces, but the mass of the car is not needed to compare the apparent weight to the normal weight. The discussion emphasizes deriving results independently for better understanding. Overall, understanding the relationship between forces is crucial for solving these types of physics problems.
Addie
Messages
9
Reaction score
0
Banked Curves involving friction

Problem: A car is traveling in a circle of a radius of 50 meters, on the surface the coefcient of static friction between the car's tires and the road is .3. With a banking angle of 30 degrees.
(I attached a diagram)

So here's what's known:
Radius: R=50 m
Coeffcient of Static Friciton: us=.3
Bank angle theta: T=30 deg

First find: Maximum velocity.
I found this by knowing...
Sum of Fx: m(v^2/r)=NsinT+UsNcosT
Sum of Fy: NcosT-UsNsinT-mg

I find by Equation = Square root of{[rg (sinT+UsCost)]/CosT-(.3 x sinT)}
IT results in Vmax= 22.8 m/s
(here is where I found that equation)

PART 2
Find the apparent weight (hint apparent wieght = Fn)

This the part I'm struggling with.

So i use my Sum of Fx to find N ;
m(v^2/r)=NsinT+UsNcosT=
m(v^2/r)=(mgcosT)sinT+Us(mgcosT)cosT
m(v^2/r)=m[(gcosT)sinT+Us(gcosT)cosT]

then I get nowhere because I divide through by M, and I need to find M or N itself and its practically impossible with just this information...
please help if you can.. any help is apreciated..
 

Attachments

  • physpic.jpg
    physpic.jpg
    11.6 KB · Views: 499
Last edited:
Physics news on Phys.org
Addie said:
First find: Maximum velocity.
I found this by knowing...
Sum of Fx: m(v^2/r)=NsinT+UsNcosT
Sum of Fy: NcosT-UsNsinT-mg
Note that Sum of Fy = 0

I find by Equation = Square root of{[rg (sinT+UsCost)]/CosT-(.3 x sinT)}
IT results in Vmax= 22.8 m/s
(here is where I found that equation)
You really should derive the results for yourself. That's the only way to learn it. (It's easy.)

PART 2
Find the apparent weight (hint apparent wieght = Fn)

This the part I'm struggling with.

You cannot find the apparent weight without knowing the mass of the car. But you can find out how the apparent weight compares to the normal weight (mg). Hint: Use your equation "Sum of Fy = 0" to solve for N.
 
Your right thanks!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top