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<Moderator's note: Moved from a homework forum.>
1. Homework Statement
Given 0 < a < 1, i = √(-1),
ei2πa = cos 2πa + i sin 2πa
but also, ei2πa = (ei2π)a = 1a = 1
How to resolve the apparent contradiction?
eab = (ea)b
eix = cos x + i sin x
No clue! This is embarrassing!
1. Homework Statement
Given 0 < a < 1, i = √(-1),
ei2πa = cos 2πa + i sin 2πa
but also, ei2πa = (ei2π)a = 1a = 1
How to resolve the apparent contradiction?
Homework Equations
eab = (ea)b
eix = cos x + i sin x
The Attempt at a Solution
No clue! This is embarrassing!
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