Basic manipulating equation algebra problem?

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The discussion centers on the manipulation of the equation kx^(2) = 2mgh + 2mgx into the form kx^(2) - 2mgh - 2mgx = 0. Participants clarify that both forms are correct, but the latter is preferred for solving using the quadratic formula. The need to multiply both sides by -1 is explained as a way to achieve a standard equation format, though it is not necessary for correctness. The conversation highlights that understanding the expected form of an equation often comes from experience rather than strict algebraic rules. Ultimately, the focus remains on the proper arrangement of terms for clarity in solving equations.
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nchin said:
How did this:
kx^(2) = 2mgh + 2mgx

Subtract 2mgh from both sides, then subtract 2mgx from both sides

i thought it's
kx^(2) = 2mgh + 2mgx
0 = 2mgh + 2mgx - kx^(2) ?
You can do it that way, too. Now multiply every term on both sides by -1
 
NascentOxygen said:
Subtract 2mgh from both sides, then subtract 2mgx from both sides


You can do it that way, too. Now multiply every term on both sides by -1

why do we need to mult both side by -1?
 
nchin said:
why do we need to mult both side by -1?
That gets you the equation that you were expecting to see, but by a different route.
 
NascentOxygen said:
That gets you the equation that you were expecting to see, but by a different route.
but what if you don't know the correct equation?

If i was doing this problem from scratch (without solution manuel)

I wouldn't have known this equation [0 = 2mgh + 2mgx - kx^(2)] was wrong because algebraically, i am correct.

is it like instincts from reading the problem to know what kind of equation to expect or something?
 
nchin said:
How did this:
kx^(2) = 2mgh + 2mgx
become this
kx^(2) - 2mgh - 2mgx = 0
Do you want to solve for x or what?
 
lep11 said:
Do you want to solve for x or what?

yes.
 
nchin said:
yes.
Okay, now you got kx^(2) - 2mgh - 2mgx = 0 so you can use the quadratic formula to solve for x.
 
nchin said:
but what if you don't know the correct equation?

If i was doing this problem from scratch (without solution manuel)

I wouldn't have known this equation [0 = 2mgh + 2mgx - kx^(2)] was wrong because algebraically, i am correct.
It's not wrong. It's perfectly correct.

In general, it is customary to arrange the terms in decreasing degree, and with the leading term having a positive coefficient, e.g., x2 - 4x + 3 = 0

But this is just for appearances (and it makes it easier to comprehend), it's not wrong if you don't do this.

Multiplying both sides does not change anything material. If you do the same thing to both sides of an equation, you change nothing.
 
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