Basic motion stuffs, time and velociton

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To determine when two particles meet, one traveling at 80 km/h and the other at 100 km/h, with the second particle starting 350 km behind, basic algebra can be applied. The equations for distance traveled by each particle can be set equal to each other, leading to the formulation of a linear system. By defining the distances in terms of time and velocities, the relative speed of the faster particle to the slower one is found to be 20 km/h. This simplifies the problem to using the formula d = vt to solve for time. Understanding the relative motion between the two particles is crucial for accurate calculations.
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Basic motion stuffs, time and velociton :(

hi
oh my gosh... i can't believe i forgotten how to do this...
i have to work out the time when will the two particles meet... where one particle (A) is traveling at a velocity of 80km/h, and (B) is traveling with a velocity of 100km/h while (B) is 350km behind (A)
(assume they are traveling toward the same directions)

thx
 
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s_a = s_b
s_a = s_0 + v_a * t
s_b = v_b * t

Insert both in first equation and calculate t.
 
Basic algebra.

Distance=rate x time

D1=x
D2=x+350
so for the equation distance = rate x time just plug in x and x+350 as your distance, use t for time
since x is the same value, you can combine the two and solve for t.
 
I'm a bit confused, do you add the 2 distances?
x+x+350=100 \\ or \\ 80? *t?
Maybe I'm stupid but I'm confused...
 
use relative time frames. Take the moving particles frame that is behind the other particle, subtract the other cars speed and no consider that the other particle is stationary.

V_{slower\ particle} = 80km/h
V_{faster\ particle} = 100km/h
V_{faster\ particle\ relative\ to\ slower\ one} = 100km/h - 80km/h = 20km/h

now your system becomes linear.

use:

d = Vt

you should know what to sub in where.

Regards,

Nenad
 
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