Lower Indices Tensor in Special Relativity: What to Know?

  • Thread starter Thread starter Palindrom
  • Start date Start date
  • Tags Tags
    Tensor
Palindrom
Messages
263
Reaction score
0
Given a tensor with upper indices in special relativity, what do I know of the corresponding tensor with lower indices? Why?
For example, for the antisymmetric tensor $\varepsilon ^{iklm} $<br />, what is $\varepsilon _{iklm} $<br />?
 
Physics news on Phys.org
How do you always find the lowered components given the upper components? The answer is contraction with the metric.
 
So now we're down to this question: What is contraction?

(thanks by the way)
 
Well the relationship is that e^iklm are the commpoents of a (4,0) tensor and e_iklm are the components of it's dual. Clearly then there's a metric function (in this case a (4,4) tensor) that maps the first tensor to it's dual and unsuprisingly this metric is related to the metric on the space of (1,0) tensors.

All you need to do is use 'inner multiplication' the metric tensor and it's dual.
 
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top