Stress Distribution in Bent Beams: Compression vs Tension

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SUMMARY

The discussion centers on the stress distribution in bent beams, specifically addressing why the inner part of a beam experiences minimum stress under compression while the outer part experiences maximum stress under tension. It is established that bending stress is not defined by the simple formula of force divided by area, as it is relative to the neutral axis of the beam. The analysis reveals that axial strains are positive on the outer side (tension) and negative on the inner side (compression), leading to positive axial stresses in tension and negative axial stresses in compression.

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chetzread
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Homework Statement


I have the bent beam like this . The inner part of beam undergo compression , right , so it shortens. Why the stress is minimum at here ?
the outer part undergo tension , why the normal stress is maximum here ?
This is from my notes
http://imgur.com/a/H8fy4

Homework Equations

The Attempt at a Solution


since the outer part elongate , the surface area is max , so it should has min stress , right ? pressure = force / area [/B]
 
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chetzread said:

Homework Statement


I have the bent beam like this . The inner part of beam undergo compression , right , so it shortens. Why the stress is minimum at here ?
the outer part undergo tension , why the normal stress is maximum here ?
This is from my notes
http://imgur.com/a/H8fy4

Homework Equations

The Attempt at a Solution


since the outer part elongate , the surface area is max , so it should has min stress , right ? pressure = force / area [/B]
Bending stress is not equal to force / area.

The terms "minimum stress" and "maximum stress" are entirely relative in beam bending.
 
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SteamKing said:
Bending stress is not equal to force / area.

The terms "minimum stress" and "maximum stress" are entirely relative in beam bending.
can you explain why bending stress is min when the beam is compressed?
 
Analysis of the kinematics of deformation shows that on the outside of the bend (relative to the neutral axis), the axial strain is positive, and, on the inside of the bend (relative to the neutral axis), the axial strain is negative. At the neutral axis, the axial strain is zero. Along with these axial strains go axial stresses, which are proportional to the axial strains. So the axial stresses are positive on the outside of the bend (tension), and the axial stresses are negative on the inside of the bend (compression).
 
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Chestermiller said:
Analysis of the kinematics of deformation shows that on the outside of the bend (relative to the neutral axis), the axial strain is positive, and, on the inside of the bend (relative to the neutral axis), the axial strain is negative. At the neutral axis, the axial strain is zero. Along with these axial strains go axial stresses, which are proportional to the axial strains. So the axial stresses are positive on the outside of the bend (tension), and the axial stresses are negative on the inside of the bend (compression).
so compression correspnds to negative(minuimum stress) tension corresponds to positive(maximum stress) ??
 
chetzread said:
so compression correspnds to negative(minuimum stress) tension corresponds to positive(maximum stress) ??
Sure.
 

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