Beats- time taken for waves to be in phase again

In summary, Homework Statement says that if the beat frequency is low, then it will take a lot of waves to be in phase again.
  • #1
somecelxis
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Homework Statement


i read some online notes. from there , i know that if the beat frequnecy ( difference in frequncies between 2 waves ) is low , then the time taken for two waves to be in phase again is very long... which means more number of waves has to be produced for two waves to be in phase again. Period of beat = 1/(f1-f2) ...Why is it so ? can someone explain in a 'physics way' ?
 
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  • #2
Has to do with simple math rules for addition of sines:
##\sin(\alpha + \beta) = \sin\alpha\cos\beta + \cos\alpha\sin\beta##
##\sin(\alpha - \beta) = \sin\alpha\cos\beta - \cos\alpha\sin\beta##
##\sin(\alpha + \beta)+\sin(\alpha - \beta) = 2\sin\alpha\cos\beta ##

Now if ##\alpha/(2\pi\,t)## is the average frequency ##f_1+f_2\over 2## and ##\beta/(2\pi\,t)## is the frequency difference ##f_1-f_2\over 2##, what do you see ?
 
  • #3
Another way: constructive interference if phase difference is ##2k\pi## (##k## integer).

Phase difference of ##\sin( 2\pi f_1 t) + \sin (2\pi f_2 t)## is ##2\pi (f_1-f_2)\,t##, so it is ##2k\pi## at intervals ##\Delta t = 1/(f_1-f_2)## as you found.
 
  • #4
BvU said:
Another way: constructive interference if phase difference is ##2k\pi## (##k## integer).

Phase difference of ##\sin( 2\pi f_1 t) + \sin (2\pi f_2 t)## is ##2\pi (f_1-f_2)\,t##, so it is ##2k\pi## at intervals ##\Delta t = 1/(f_1-f_2)## as you found.

as the (f1-f2) increases, Period of beat = 1/(f1-f2) decreases. i knew this ... but this only involve maths ... can you explain in a 'physics' way?
 
  • #5
There's nothing physical. The sines are just a description in math language.
See the ball n+1 catching up with ball n in the video or this one . A whole bunch of (co)sines going in and out of phase. The stunning group effect has "nothing" to do with the movement of the individual pendula.

It's yet another approach, but still math: if f2= f1 * (1+ε), the second wave catches up a fraction ε of a period for each full period of the first. After 1/ε of these periods the two are in phase again. Physics = mathematics here, sorry about that !
 

1. What are beats and why do they occur?

Beats are a phenomenon that occurs when two waves with slightly different frequencies interfere with each other. This interference creates a periodic variation in the overall amplitude of the combined wave. Beats occur because the waves are not perfectly in phase, meaning they do not have the same starting point or frequency.

2. How is the time taken for beats to occur calculated?

The time taken for beats to occur is calculated using the formula T = 1/(|f1 - f2|), where T is the time period and f1 and f2 are the frequencies of the two interfering waves. This formula assumes that the frequencies are close together and that the amplitudes of the waves are similar.

3. What factors affect the time taken for beats to occur?

The time taken for beats to occur is primarily affected by the difference in frequency between the two interfering waves. A larger difference in frequency will result in a shorter time period for the beats. Other factors such as the amplitude and phase of the waves can also affect the time taken for beats to occur.

4. How does the speed of the waves affect the time taken for beats to occur?

The speed of the waves does not directly affect the time taken for beats to occur. However, the speed of the waves does affect their frequency, which in turn affects the time period for the beats. Higher wave speeds result in higher frequencies and shorter beat periods.

5. Can beats occur between any type of waves?

Beats can occur between any type of waves as long as they have slightly different frequencies and similar amplitudes. This includes sound waves, light waves, and other types of electromagnetic waves. However, the occurrence and perception of beats may vary depending on the properties of the specific type of wave.

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