Behavior of a graph at a point

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The discussion focuses on the behavior of the function y = cubicroot(x + 2) at x = -2. Participants analyze the characteristics of differentiability, corners, cusps, vertical tangents, and discontinuities. It is established that the function has a value at x = -2, ruling out discontinuity. The conclusion reached is that the function exhibits a vertical tangent at this point, while corners and cusps do not apply based on the definitions provided. Ultimately, the behavior at x = -2 is identified as a vertical tangent.
Jacobpm64
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Which of the following describes the behavior of y = cubicroot(x + 2) at x = -2

(A) differentiable
(B) corner
(C) cusp
(D) vertical tangent
(E) discontinuity

well i graphed the function, and I'm not sure.. i know for sure it isn't E... because f(-2) = 0... it has a value.. uhmm.. as for the rest I'm not sure.. i don't even know what a corner and a cusp is.
 
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Well, a cusp is when the second derivative of the function (which measures curvature) decreases or increases on both sides, making an upside down v or right-side up v.

A corner can be described if f is not differential at any point where the secant lines have different limits as they approach a point (it looks like a corner). So can vertical tangency (if point looks like it's derivative would be vertical).

If I were you I would look at what it cannot be.
 
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as for corner.. that just completely and utterly confuses me ;\

let's see..

so, hmm... we know it isn'tA, we aren't sure about B, we know it can't be C, we know it is D, and we know it can't be E..

So we're left with Discussions about B..

am i correct thus far?
 
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A "corner" occurs when the derivative does not exit- but the limits of the derivatives from above and below exist but are different. A "cusp" occurs when the two one sided limits of the derivative do not exist.
 
so it's none of those... and the answer is only a vertical tangent
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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