Does the Violation of Bell Inequality Challenge Quantum Mechanics?

efaizi
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Does the Bell inequality confirms the quantum mechanics? If answer is yes, why the violation of Bell inequality is more famous?
 
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efaizi said:
Does the Bell inequality confirms the quantum mechanics? If answer is yes, why the violation of Bell inequality is more famous?

It doesn't confirm QM, but it does claim that no theory with Local Hidden Variables can match the predictions of Quantum Mechanics. The only theory to survive the move from locality to Non-Locality with their Hidden Variable(s) intact is the de Broglie-Bohm Interpretation, which is empirically on the same footing as QM for now.

Of course, SQM violates Bell's Inequalities, soooo... ?! Who knows.
 

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Thread 'Schrödinger equation and classical wave equation'

Not an expert in QM. AFAIK, Schrödinger's equation is quite different from the classical wave equation. The former is an equation for the dynamics of the state of a (quantum?) system, the latter is an equation for the dynamics of a (classical) degree of freedom. As a matter of fact, Schrödinger's equation is first order in time derivatives, while the classical wave equation is second order. But, AFAIK, Schrödinger's equation is a wave equation; only its interpretation makes it non-classical...
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Thread 'Lesser Green's function'

Thread 'Lesser Green's function'

The lesser Green's function is defined as: $$G^{<}(t,t')=i\langle C_{\nu}^{\dagger}(t')C_{\nu}(t)\rangle=i\bra{n}C_{\nu}^{\dagger}(t')C_{\nu}(t)\ket{n}$$ where ##\ket{n}## is the many particle ground state. $$G^{<}(t,t')=i\bra{n}e^{iHt'}C_{\nu}^{\dagger}(0)e^{-iHt'}e^{iHt}C_{\nu}(0)e^{-iHt}\ket{n}$$ First consider the case t <t' Define, $$\ket{\alpha}=e^{-iH(t'-t)}C_{\nu}(0)e^{-iHt}\ket{n}$$ $$\ket{\beta}=C_{\nu}(0)e^{-iHt'}\ket{n}$$ $$G^{<}(t,t')=i\bra{\beta}\ket{\alpha}$$ ##\ket{\alpha}##...
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