Bell's inequality when efficiency < 1

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    Efficiency Inequality
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SUMMARY

This discussion focuses on the implications of detector efficiency (\(\eta < 1\)) in Bell's inequality. The equation \(\langle ab \rangle_{coinc} = \langle ab \rangle / (\eta_A \eta_B)\) is critical for understanding how conditional expectations must increase when efficiency is less than one. The algebraic derivation shows that the expected value of Bell's theorem is modified to \(Bell \leq (4/\eta) - 2\), highlighting the need to account for detection probabilities in quantum experiments.

PREREQUISITES
  • Understanding of Bell's theorem and its significance in quantum mechanics
  • Familiarity with conditional probability and expectation values
  • Knowledge of quantum detection efficiencies and their impact on experimental results
  • Basic algebraic manipulation skills in the context of probability theory
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  • Study the derivation of Bell's inequality under different efficiency conditions
  • Explore the implications of detector efficiency on quantum entanglement experiments
  • Learn about the mathematical foundations of conditional probabilities in quantum mechanics
  • Investigate real-world applications of Bell's theorem in quantum information science
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Quantum physicists, researchers in quantum mechanics, and students studying the implications of detector efficiency in quantum experiments will benefit from this discussion.

naima
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Hi PF

Somebody gave me this link
could you help me to understand why (9) has to be inserted in (7) when the efficiency [tex]\eta < 1?[/tex]
 
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I think that a part of the answer is here
but i do not understand eq (6):
[tex]<ab>_{coinc} = <ab>/(\eta_A \eta_B)[/tex]
why do this conditional expectation must grow?
 
I found the algebric origin of the fact that in Bell's theorem we replace 2 by [itex]4/\eta - 2[/itex]
suppose that a detector has a probability [itex]\eta[/itex] to detect a particle
we have four possibilities when a pair is created:
1) left and right not detected
2) left detected but not right
3) right detected but not left
4) left and right detected
the probabilities are:
[tex](1 - \eta)^2[/tex]
[tex]\eta (1 - \eta)[/tex]
[tex](1 - \eta)\eta[/tex]
[tex]\eta^2[/tex]
the observer cannot count the first case events
We have 2) + 3) + 4) = [itex]1 - (1 - \eta)^2) = (2 - \eta) \eta[/itex]
the conditional probability of 4) knowing that 1) did not occur is
[tex]\frac{\eta^2 }{ (2 - \eta) \eta} = \eta/(2 - \eta)[/tex]
the expected value Bell = [itex]\eta/(2 - \eta)<=2[/itex] implies [itex]Bell <= (4/\eta) - 2[/itex]
 

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