Bernoulli equation application

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
6 replies · 1K views
Chemist@
Messages
115
Reaction score
1
Why is the water level in the object above the water level of the current? How to apply Bernoulli equation in this case?
 

Attachments

  • untitled.GIF
    untitled.GIF
    1.6 KB · Views: 562
Physics news on Phys.org
The water level in the object is above the water level in the current because the current is supplying enough pressure to push the water that high. The current has a velocity, and you can probably imagine that faster velocity entails a higher water level in the object. There is also a distance involved, which is the height of the fluid in the object. Velocity, pressure, and distance are all part of Bernoulli's equation.
 
I know all that, but how would the equation look like in this case.
 
I know the standard form. What must be the velocity so that the water level in the object is above the normal level? Is it: V>sqrt(2pa/ro)
 
Could you please elaborate why?