Bernoulli equation application

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The water level in the object is higher than in the current due to the pressure generated by the current's velocity. According to Bernoulli's equation, the relationship between velocity, pressure, and height determines the water level. A faster current velocity leads to increased pressure, allowing water to rise higher in the object. The equation suggests that any velocity will elevate the water level in the pipe, as the pressure differential is sufficient to counteract gravity. Understanding these principles is essential for applying Bernoulli's equation accurately in this scenario.
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Why is the water level in the object above the water level of the current? How to apply Bernoulli equation in this case?
 

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The water level in the object is above the water level in the current because the current is supplying enough pressure to push the water that high. The current has a velocity, and you can probably imagine that faster velocity entails a higher water level in the object. There is also a distance involved, which is the height of the fluid in the object. Velocity, pressure, and distance are all part of Bernoulli's equation.
 
I know all that, but how would the equation look like in this case.
 
It's the standard/most common form of the equation. Have you looked it up?
 
I know the standard form. What must be the velocity so that the water level in the object is above the normal level? Is it: V>sqrt(2pa/ro)
 
For your sketch, any velocity will cause the water level in the pipe to rise.
 
Could you please elaborate why?
 
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