Bernoulli Numbers, Euler-Maclauring Formula - Math Methods class

Click For Summary

Homework Help Overview

The discussion revolves around the Bloch-Gruneissen approximation for resistance in monovalent metals, specifically focusing on deriving expressions for resistance as temperature approaches infinity and zero. The context includes concepts from Bernoulli numbers and the Euler-Maclaurin formula.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the approach to simplifying the integrand for the first part of the problem and question the validity of term-by-term integration. There is also consideration of how to handle the limits of integration. For the second part, there is speculation about using definitions of Bernoulli numbers and expanding terms in powers of e^{-x}.

Discussion Status

Participants are actively engaging with the problem, offering suggestions for approaches and clarifying misunderstandings. There is a recognition of the need to expand terms and check for signs in the expansions, indicating a productive exploration of the problem.

Contextual Notes

There is mention of the upper limits of integration changing based on temperature conditions, and participants are navigating the complexities of LaTeX formatting for their equations.

kde2520
Messages
16
Reaction score
0

Homework Statement


The Bloch-Gruneissen approximation for the resistance on a monovalent metal is

[tex]\rho[/tex]=C(T[tex]^{5}[/tex]/[tex]\Theta[/tex][tex]^{6}[/tex])[tex]\int[/tex][tex]^{\Theta/T}_{0}[/tex][tex]\frac{x^{5}dx}{(e^{x}-1)(1-e^{-x})}[/tex]

(a)For T->[tex]\infty[/tex], show that [tex]\rho[/tex]=(C/4)(T/[tex]\Theta^{2}[/tex])

(b)For T->0, show that [tex]\rho[/tex]=5![tex]\zeta(5)[/tex]C[tex]\frac{T^{5}}{\Theta^{6}}[/tex]


Homework Equations


The section is on Bernoulli numbers and the Euler-Maclaurin Formula. Several definitions including x/(e^x-1)=sum->(Bn*x^n)/n!, Bernoulli Polynomials, Reimann-Zeta function, etc.


The Attempt at a Solution


For part (a) I see that as T->infinity the upper integration limit goes to zero, thus I may approximate the integrand giving (as the integrand) x^5/[(x+x^2/2!+x^3/3!+...)(-x+x^/2!-x^3/3!+...)]. Can I just multiply this out, simplify, and integrate term by term? If so, over what integration limits?

For part (b) the upper limit goes to infinity so I'm guessing I need to do the integral by substituting some definition of the Bernoulli Numbers?...

Help...

PS - Sorry if the equations are unclear. I'm new to LaTex. Help with that would be appreciated too.
 
Physics news on Phys.org
kde2520 said:
Can I just multiply this out, simplify, and integrate term by term?

Yep! (You have a sign wrong though ...)
kde2520 said:
If so, over what integration limits?

Same as before, you just think of the upper limit as a small parameter.
kde2520 said:
For part (b) the upper limit goes to infinity so I'm guessing I need to do the integral by substituting some definition of the Bernoulli Numbers?...

Try expanding everything but the [itex]x^5[/itex] in powers of [itex]e^{-x}[/itex].

As for LaTeX, just put the beginning and ending tex and /tex commands around the whole equation:

[tex]\rho=C(T^{5}/\Theta^{6})\int^{\Theta/T}_{0}\frac{x^{5}dx}{(e^{x}-1)(1-e^{-x})}[/tex]
 
I guess you mean the sign is wrong in the expansion of [tex]e^{-x}[/tex]? What is it's expansion?
 
Avodyne said:
Try expanding everything but the [itex]x^5[/itex] in powers of [itex]e^{-x}[/itex].

Isn't that what we did for part (a)?

Thanks for the LaTex tip!
 
I mean an expansion like

[tex]{1\over 1-e^{-x}}=\sum_{n=0}^\infty (e^{-x})^n[/tex]
 

Similar threads

Replies
4
Views
4K
Replies
13
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K