x/((e^x)-1)= 1 + B1x+B2((x^2)/2!) + B3((x^3)/3!)+…
where Bn are called the Bernoulli numbers. Determine B1 , B2 and B3.
I think this one: (1+x)^n = 1 + nx + ((n)(n-1)/2!)(x^2)+...
The Attempt at a Solution
i wrote it in this form -x(1-e^x)^(-1) to perhaps make it easier to use the maclaurin series but i still don't get what the question asks us to get