Bernoulli/Pascal Tarpaulin Problem

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The discussion revolves around calculating the wind speed required for a flat rectangular roof (4.0m x 5.5m) to withstand a maximum outward force of 21,000 N, using Bernoulli's equation and Pascal's principle. The density of air is given as 1.29 kg/m^3, and the initial velocity is assumed to be zero. The attempt at a solution involves equating forces and considering the momentum of air impacting the roof. A side question about Archimedes' principle confirms that the weight of displaced fluid can be calculated using the volume of the fluid and its density. The conversation emphasizes the importance of understanding fluid dynamics in relation to structural integrity under wind pressure.
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Bernoulli/Pascal "Tarpaulin" Problem

Homework Statement



"The construction of a flat rectangular roof (4.0m x 5.5m) allows it to withstand a maximum net outward force of 21 000 N. The density of the air is 1.29 kg/m^3. At what wind speed will this roof blow outward?"

A1=22m^2
F=21000 N
p=1.29
v1=0?

Homework Equations



Bernoulli's Equation:
P1-1/2p(v1)^2+pgy1=P2+1/2(v2)^2+pgy2

Pascal's Principle?
F2=F1*(A2/A1)


The Attempt at a Solution



1/2(1.29)v1^2=1/2(1.29)v2^2

I believe this has something to do with Pascal's Principle, but I'm not quite sure.

2100=F1(A2/22)

From here, I'm completely lost.




On a side note, I have a quick question on Archimedes' Principle. The weight of the displaced fluid is normally found through the volume of the displaced fluid and the given density, correct?


Thanks in advance.
 
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The wind is blowing at a speed of v. Think of a volume of air with cross-sectional area A and length vt, which is adjacent to the wall of area A and blowing toward the wall. In exactly time t, all of this air would collide with the wall, and impart its momentum to the wall. The momentum of the air after collision is zero in the direction it was blowing, because it will disperse horizontally after hitting the wall. (This may not be exactly true, but we have to idealise the situation.) So,

Change in momentum of this air = Mass of this air*(difference in initial and final velo)
= impulse given to the wall in time t
=>
(Vol of air)*(density of air)*v = F*t, where vol of air is vt.

Plug in the numbers to get the force.

What you asked in the side note is also correct. It can also be found if you know the weight of the object floating in the liquid.
 
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