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notagenius08
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Homework Statement
A water tank of height h has a small hole at height y. The water is replenished to keep h from changing. The water squirting from the hole has range x. The range approaches zero as y goes to 0 because the water squirts right onto the table. The range also approaches zero as y goes to h because the horizontal velocity becomes zero. Thus there must be some height y between 0 and h for which the range is a maximum.
a)Find an algebraic expression for the flow speed v with which the water exits the hole at height y.
b)Find an algebraic expression for the range of a particle shot horizontally from height y with speed v.
c)Combine your expressions from parts A and B. Find the maximum range x_max
d)Find the height y of the hole.
Homework Equations
v1A1=v2A2
p1+.5(density)v1^2+(density)gy1=p2+.5(density)v2^2+(density)gy2
deltaK+deltaU=Wext
The Attempt at a Solution
a)Solving for v2(assuming this is outside the can velocity):
v=sqrt of 2p1/denisty-2p2/density+v1^2+2gy1-2gy2
computer told me to check my answer, so I guess its wrong.
b)distance=rate*time
t=sqrt of 2h/g
x=v*t
haven't tried part c or d cause I can't get part a) right.
Thanks for any help.
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