- #1

wmrunner24

- 58

- 0

So, what I've figured from the problem and what I've learned so far about flow continuity and Bernoulli's principle gave me this.

FR=A

_{1}v

_{1}

FR=A

_{2}v

_{2}

Flow rate = Area of a Cross-section * Velocity

So, I can find the velocity for Bernoulli's equation.

P

_{1}+ [tex]\rho[/tex]gh

_{1}+ 1/2[tex]\rho[/tex]v

_{1}

^{2}= P

_{2}+ [tex]\rho[/tex]gh

_{2}+ 1/2[tex]\rho[/tex]v

_{2}

^{2}

And since there's no change in height at the first pipe cross-section, [tex]\rho[/tex]gh

_{1}= 0, right?

P

_{1}+ 1/2[tex]\rho[/tex]v

_{1}

^{2}= P

_{2}+ [tex]\rho[/tex]gh

_{2}+ 1/2[tex]\rho[/tex]v

_{2}

^{2}

So, then I solve for P

_{2}, but since it wants gauge pressure, I have to subtract atmospheric pressure, which means that I can remove P

_{1}from the equation, because the problem statement says it equals atmospheric pressure, right?

1/2[tex]\rho[/tex]v

_{1}

^{2}- 1/2[tex]\rho[/tex]v

_{2}

^{2}- [tex]\rho[/tex]gh

_{2}= P

_{g}

All I'm really looking for here is a logic check for this much of it. Am I right?

All help is greatly appreciated.