- #1
Sigma Rho
- 7
- 0
Here's my problem:-
A horizontal tube has a T-junction with a vertical tube coming downwards into a container of liquid, at height h below the T-junction. Air is forced into the horizontal tube which causes a pressure difference which sucks the liquid up the vertical tube.
What is the pressure at the top of the vertical tube?
I have the answer as
P = Po - 1/2 * /rhoA * v^2
where:
P = pressure at top of vertical tube
Po = atmospheric pressure
/rhoA = density of air in tube
v = velocity of air in tube
but I can't seem to derive this equation from Bernoulli's equation. (Or anything else! )
Any ideas?
Thanks.
A horizontal tube has a T-junction with a vertical tube coming downwards into a container of liquid, at height h below the T-junction. Air is forced into the horizontal tube which causes a pressure difference which sucks the liquid up the vertical tube.
What is the pressure at the top of the vertical tube?
I have the answer as
P = Po - 1/2 * /rhoA * v^2
where:
P = pressure at top of vertical tube
Po = atmospheric pressure
/rhoA = density of air in tube
v = velocity of air in tube
but I can't seem to derive this equation from Bernoulli's equation. (Or anything else! )
Any ideas?
Thanks.