Beta Decay: 14C6 → 14N7+ e− + νe

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Crystal037
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Homework Statement
In beta-decay, a gamma ray that is a fast moving electron is emitted due to the conversion of a neutron to a proton and an electron to increase the stability. As a result, the atomic number increases while the mass number remains the same. But when the atomic no. increases as an extra proton is added, won't the atom need the electron it emits to stabilise the atom which by now has a positive charge
Relevant Equations
Eg: 14C6 → 14N7+ e− + νe
Problem Statement: In beta-decay, a gamma ray that is a fast moving electron is emitted due to the conversion of a neutron to a proton and an electron to increase the stability. As a result, the atomic number increases while the mass number remains the same. But when the atomic no. increases as an extra proton is added, won't the atom need the electron it emits to stabilise the atom which by now has a positive charge
Relevant Equations: Eg: 14C6 → 14N7+ e− + νe

According to me, The atom as its electron has been shot out would have a positive charge.
 
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Crystal037 said:
Problem Statement: In beta-decay, a gamma ray that is a fast moving electron is emitted due to the conversion of a neutron to a proton and an electron to increase the stability. As a result, the atomic number increases while the mass number remains the same. But when the atomic no. increases as an extra proton is added, won't the atom need the electron it emits to stabilise the atom which by now has a positive charge
Relevant Equations: Eg: 14C6 → 14N7+ e− + νe

The atom as its electron has been shot out would have a positive charge.
Yes, this is called an ion.

Note that a beta particle is not a gamma ray.
 
Then how does the ion gets an electron to stabilize itself