Beta+ Decay in Z>N Nuclei: Pauli Term Explanation

  • Thread starter Thread starter arivero
  • Start date Start date
  • Tags Tags
    Beta Decay
arivero
Gold Member
Messages
3,481
Reaction score
187
I have just noticed that the nuclei with Z slightly greater than N have a peculiar pattern of b+ decay. Do someone know if this is justified from the Pauli Term of Weizsaecker formula?

Just I hope I have not found another unknown phenomena :-)


[EDITED:] The phenomena is more apparent for Z=N+1, but just for these nuclei the Pauli Term {(N-Z)^2\over A} is zero, and only the EM term Z^2/A^{1/3} contributes to decay energy.
 
Last edited:
Physics news on Phys.org
arivero said:
I have just noticed that the nuclei with Z slightly greater than N have a peculiar pattern of b+ decay. Do someone know if this is justified from the Pauli Term of Weizsaecker formula?

Just I hope I have not found another unknown phenomena :-)


[EDITED:] The phenomena is more apparent for Z=N+1, but just for these nuclei the Pauli Term {(N-Z)^2\over A} is zero, and only the EM term Z^2/A^{1/3} contributes to decay energy.

What is peculiar about what you see?
 
Well, for instance if you plot log(energy) vs log(halflife) you will notice that the data points adjust to two clearly distinct slopes.

Or, if you plot log(halflife), or halflife directly, versus atomic number A, you can notice two different groupings, depending of Z being greater or smaller than N. One of them does not present dependence on A, but the other clearly depends on A (or Z or N if you prefer).
 
Can you post the graphs or a link to them?
 
I'll try to upload some plot tomorrow Monday from the fac.

I think I could cope with the existence of a dependence Energy(AtomicNumber) for Z=N+1 even if the EM term does not fit well, because the dropplet model has another terms, such as Z^2 A^{1/3}, that could take responsability for this.

I am more intrigued about the difference in the dependence HalfLife(Energy) depending if the beta decay occurs for Z>=N or Z<N, ie, if the decaying proton goes to a lower neutron shell or to an upper one. It is not unexpected, but I would like to heard if people is usually able to get some properties of beta decay from this. Of course, the first step is to know if textbooks report this difference.
 
Here are the plots

Hoping moderator approval, here are the plots I was speaking about. The second one, bpluslogT(A).jpg , shows decay time versus mass number for all the beta rays with intensity greater than 50%. The first one show log(E) versus Log(T), and the lower cluster corresponds very well to the hiperbole in the former plot.

I should say we are seeing the typical clusterings depending on if the transition is superallowed, allowed, etcetera... (a senior has been kind enough to partly confirm this). But still, it is impressive.
 

Attachments

  • bpluslogTlogE.jpg
    bpluslogTlogE.jpg
    8.8 KB · Views: 556
  • bpluslogT(A).jpg
    bpluslogT(A).jpg
    10.9 KB · Views: 432
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Back
Top