Bifurcations in a harmonic oscillator equation

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This discussion focuses on determining bifurcation values in a harmonic oscillator represented by the second-order differential equation \(\frac{d^2y}{dx^2} + B\frac{dy}{dx} + Cy = 0\). The parameters of interest are the spring constant α and the damping coefficient β, which influence the characteristic equation \(r^2 + Br + C = 0\). Bifurcations occur when the discriminant \(\sqrt{B^2 - 4C}\) equals zero, leading to distinct behaviors based on the nature of the roots: two real roots, a single real root, or two complex roots, which correspond to oscillatory motion.

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smithnya
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Hello everyone,

I've been trying to figure out how to determine bifurcation values in a harmonic oscillator when either the spring constant α or damping coefficient β act as undefined parameters. I understand bifurcations in first-order DEs, but I can't figure them out in a second-order equation such as a harmonic oscillator. Could anyone give me an explanation or tip on how to achieve this?

Thanks in advance
 
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The general second order, constant coefficients, homogeneous linear differential equation can be written
\frac{d^2y}{dx^2}+ B\frac{dy}{dx}+ Cy= 0

Yes, this can be interpreted as the motion of a spring where 'B' gives the damping and 'C' the spring force. The characteristic equation for this would be r^2+ Br+ C= 0 which can be solve by the quadratic equation:
r= \frac{-B\pm\sqrt{B^2- 4C}}{2}[/quote]<br /> <br /> That equation has either (a) two real roots, (b) a single real root, (c) two complex roots (which gives oscilatory motion) depending upon the discriminant, \sqrt{B^2- 4C}. The solution &quot;bifurcates&quot; when that is 0.
 
Thanks so much. So what happens when you end up with complex roots or with two distinct roots?
 

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