you may think, why is the entropy of the matter immediately after the big bang so low, even though it is spread out very evenly?
let me offer a small opinion as to why. can we agree to the 2 following facts?
the matter after the big bang is not a black hole.
the entirety of matter after the big bang is a gravitating system.
For a classical gas kinetic energy <K> = 3/2*kT. In contrary to conventional notation, due to T being occupied by the temperature, K will instead be used for the kinetic energy.
A self gravitating system obeys the virial theorem because the kinetic and potential energies, and the momenta, of all particles, are bounded. <K> = -1/2 <U> where <U> is the time average of the potential energy. The proof is long so let's take an example instead: the 2 body central force problem.
U = -GmM/R (gravitational potential)
F_{g} = -GmM/R^{2} (gravitational force)
F_{c} = mv^{2}/R (centrifugal force)
at equilibrium and in appropriate coordinates the net force is zero.
GmM/R^{2} = mv^{2}/R
rearrange to get (1/2)mv^{2} = (1/2) GmM/R
oh look we have K = -(1/2)U. If it works for 2 particles, maybe it works for N particles.
So K = -(1/2)U, U = -2K. total energy E = K + U = K - 2K = -K.
K = (3/2)kT. So E = -(3/2)kT
In other words, total energy = -number*temperature, and as temperature increases, E is decreasing.
What is gravitational potential energy of a sphere of gas?
http://scienceworld.wolfram.com/physics/SphereGravitationalPotentialEnergy.html
U = -3GM^{2}/R.
So E = -number*1/R -> T = number/R. As R decreases T increases. As T increases, E decreases.
This means that self gravitating systems want to decrease their energy by decreasing their size (measured by radius R) and increasing temperature. The uniform state after the big bang is therefore a state with extremely low entropy and favored to evolve towards higher entropy states. Indeed, energy would be minimized if R approached zero.