Bingo game at the nearby nursing home

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Discussion Overview

The discussion revolves around the probability of a player covering all spaces on a bingo card with a specific number of calls remaining. Participants explore the mathematical implications of the bingo game setup, including the distribution of numbers and the conditions for achieving a "blackout" (covering all spaces). The conversation includes both theoretical and practical aspects of bingo probabilities.

Discussion Character

  • Mathematical reasoning
  • Exploratory
  • Debate/contested

Main Points Raised

  • One participant describes a scenario where a player covers all 25 spaces with 17 numbers yet to be called, questioning the odds of this occurrence.
  • Another participant suggests that the odds might be approximately 1:5,000 to 1:10,000 games for such a coincidence to happen.
  • Discussion includes the permutations of the 75 numbers and how many cards would be filled at a certain point in the game, particularly the 58th number called.
  • Several participants inquire about the probability of covering all spaces without calling "BINGO!" and discuss the implications of having remaining calls.
  • One participant calculates the probability of a blackout after 58 numbers called, providing a formula involving combinations.
  • Another participant questions whether each column should be treated individually in calculating probabilities, while a different participant asserts that the overall subset of numbers is what matters for blackout calculations.
  • Clarifications are made regarding the uniqueness of numbers on a bingo card and the implications of having a free space.

Areas of Agreement / Disagreement

Participants express differing views on the calculation methods for probabilities, with some agreeing on the mathematical approach while others propose alternative considerations. The discussion remains unresolved regarding the exact probabilities and methods for calculating them.

Contextual Notes

Participants note the importance of the column restrictions in bingo and how they affect valid card configurations, but there is no consensus on how these should influence probability calculations.

Loren Booda
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I run a bingo game at the nearby nursing home. The other day a lady covered all of the 25 [5x5] spaces on her card with 17 numbers yet to call. If there are 75 numbers to call at the beginning of the game, and the numbers are distributed in columns randomly among 1-15 under "B," 16-30 under "I," 31-45 under "N," 46-60 under "G," and 61-75 under "O" on a given card (with a "free" space in the central square), what are the odds that she could cover her card with at least 17 numbers to call?
 
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Give this another try, mathematicians; approximate if necessary. The lady at the nursing home for whom these odds occurred (and I, too) are quite curious as to what they might actually be. My guess is 1:5,000 to 1:10,000 games have such a coincidence.
 
Meh, I'll stick out my neck to try to get something going. Maybe it would be easiest to start with all the permutations of your set of 75 numbers since you presumably want the 58th number to be one of the 24 on your card. A game is just a permutation of those 75 numbers. There are 75! games. I can see at least two questions that you might be asking (which, for all I khow, might be the same question). For a given game, how many cards would be filled on the 58th turn? For a given card, how many games would fill it on the 58th turn?

Can the same number appear more than once on a card?
 
Last edited:
I'd like to know what the probability is of covering all 25 spaces WITHOUT shouting BINGO??
 
honestrosewater,

A given number can appear only once on a card (in the appropriate column, too), as your factorial seems to indicate.

My question is for a given card.

Thanks.
 
Tide said:
I'd like to know what the probability is of covering all 25 spaces WITHOUT shouting BINGO??

Well, if you get a line, and there is still 50 calls left, you don't shout BINGO!

17 calls left is still quite a bit.
 
JasonRox said:
Well, if you get a line, and there is still 50 calls left, you don't shout BINGO!

17 calls left is still quite a bit.

I thought the object was just to fill a line - shows how much I know about BINGO! :)
 
Tide said:
I thought the object was just to fill a line - shows how much I know about BINGO! :)

If you get a line early on during the game, you wait.

You have to be quick though. So that when someone calls BINGO!, you call it quickly afterwards.

That way it was a tie, and you also took the chance to try and win more.

Note: I don't play BINGO!
 
There's usually a free space, so 24 numbers on the card and 51 not on it right? With 58 numbers called you'd have C(51,34) ways of having a black out, the total number of ways the 34 of the 51 numbers off the card can be called. There are C(75,58) ways to choose 58 numbers, so the probability of a blackout after 58 numbers would be C(51,34)/C(75,58)=.0004977832...

This is including the event that you had a blackout before call 58 as well.

(here C(n,r)=n!/(r!(n-r)!) is the usual "n choose r")
 
  • #10
Thanks for wresting an answer, shmoe! I do believe it's approximate, though. Shouldn't each column (B, I, G, O) be treated individually as 5 chances out of 15, excepting column N, 4 chances out of 15?
 
  • #11
No, it's exact. With respect to a blackout, your bingo card is just a subset of 24 numbers from the 75, the columns don't matter (nor do the positions within the columns). Of course not all subsets of these 24 numbers can form a valid bingo card due to the column restrictions, but that's not relevant here.

If you'd like a second opinion, see:

http://wizardofodds.com/bingo
 
  • #12
That's quite a second opinion! Thanks times two, shmoe.
 

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