Binomial Expansion: Coefficient of p4q7 in (2p-q)(p+q)10

AI Thread Summary
To find the coefficient of p^4q^7 in the expansion of (2p-q)(p+q)^10, the binomial expansion theorem is essential. Users discuss the need to expand (p+q)^10 and then multiply the resulting terms to isolate p^4q^7. There is some confusion regarding the correct method of expansion, with one user clarifying that (2p-q)(p+q) cannot be simplified as suggested. The conversation emphasizes understanding the binomial expansion to avoid unnecessary complexity in calculations. Overall, the thread highlights the importance of mastering binomial expansion for solving such problems effectively.
look416
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Homework Statement


Determine the coefficient of p4q7 in the expansion of (2p-q)(p+q)10

Homework Equations


The Attempt at a Solution


sry, i can't attempt to solve this coz i don't even know how to expand this using formula
 
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Do you know how to expand (a+b)n using the binomial expansion?
 
well i know
but does this related to (a+b)n
 
extremely required help
 
look416 said:
well i know
but does this related to (a+b)n

look416 said:
extremely required help

because you can expand out (p+q)10 and you can multiply out the terms which will give you p4q7
 
might help, to see what rockfreak is implying, if you write it as
(2p)(p+q)10 - q(p+q)10

now think about which terms you need to look at for p4q7
 
lanedance said:
might help, to see what rockfreak is implying, if you write it as
(2p)(p+q)10 - q(p+q)10

now think about which terms you need to look at for p4q7

well that one is definitely wrong
because (2p-q)(p+q) is not equal to (2p)(p+q) - q(p+q)
 
rock.freak667 said:
because you can expand out (p+q)10 and you can multiply out the terms which will give you p4q7

well no other methods?
because this method will definitely cause a lot of hardwork:frown:
 
look416 said:
well that one is definitely wrong
because (2p-q)(p+q) is not equal to (2p)(p+q) - q(p+q)

really? try multiplying both sides out
 
  • #10
look416 said:
well no other methods?
because this method will definitely cause a lot of hardwork:frown:

if you use the binomial expansion theorem, this will tell you what the terms are without doing all the multiplication. do you know what the binomial expansion theorem is?

you just have to decide which terms you want to find - see previous post
 
  • #12
lanedance said:
have a look at this to find out about the binomial expansion

http://en.wikipedia.org/wiki/Binomial_theorem

lanedance said:
if you use the binomial expansion theorem, this will tell you what the terms are without doing all the multiplication. do you know what the binomial expansion theorem is?

you just have to decide which terms you want to find - see previous post

lanedance said:
really? try multiplying both sides out

hay hay hay buddy, chill out
maybe i doesn't know binomial expansion very well, but you don't have react so...:frown:
just now i comment you are wrong just because normally the multiplying of two terms are not like that...
just sorry for offended you
 
  • #13
no offence, just trying to help out
 
  • #14
if you are not offended that's good
thx for your help
you and rock.freak667's help is much appreciated
 
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