Biot Savart Law Calculation problems

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SUMMARY

The forum discussion focuses on calculating the magnetic field using the Biot-Savart Law, specifically for a proton with a given velocity and position vector. The equation used is B⃗ = μ/4π * (qv x r) / r², with μ/4π set to 10^7, charge q as 1.6e-19, and the cross-product v x r as <0,0,6.2e4>. The user attempts to substitute these values but arrives at an incorrect result of 1.8413e-5, indicating a misunderstanding in the application of the formula or unit considerations.

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Homework Statement


Find the magnetic field from a proton at location r, with velocity v, if the cross-product of vxr is <0,0,6.2e4> and the magnitude of r is 7.34e-2

Homework Equations



B⃗ =μ/4π * qv x r /r^2

The Attempt at a Solution


Substituting in 10^7 for μ/4π
1.6e-19 for q
<0,0,6.2e4> for v x r
and (7.34e-2)^2 for r^2

I get 1.8413e-5. This is not the right answer, so I must be doing something wrong. I thought you simply had to substitute in the variables and calculate. Could someone give me a hint?
 
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