Bivectors, Cartan Geometry and Curvature

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I have some questions related to bivector space, the curvature tensor and Cartan geometry.

1) Because of its antisymmetric properties

R_{\mu\nu\alpha\beta}=-R_{\nu\mu\alpha\beta}, R_{\mu\nu\alpha\beta}=-R_{\mu\nu\beta\alpha},

the Riemann curvature tensor can be regarded as a second-rank bivector R_{AB} in six-dimensional space (in case of spacetime dimension four). Due to the symmetry

R_{\mu\nu\alpha\beta}=R_{\alpha\beta\mu\nu},

one can also conclude that R_{AB}=R_{BA}. My question now is, which of the symmetry properties remain when extending Riemannian geometry to Cartan geometry with a non-symmetric Ricci-Tensor? Is it correct that one can still obtain a bitensor R_{AB}, which then however is non-symmetric?

2) The six-dimensional space is of signature (+++---). Is there any analogue to Lorentz transformations in this space?

3) The metric g_{AB} in bivector space can be constructed by

g_{\mu\nu\rho\sigma} = g_{\mu\rho}g_{\nu\sigma}-g_{\mu\sigma}g_{\nu\rho}.

I guess from that one can derive a curvature tensor R_{ABCD} for the six-dimensional space. Is that correct? And is there any interpretation for the bitensor representation R_{AB} of R_{\mu\nu\alpha\beta}?

Any answers highly appreciated!

Cheers
 
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Sorry, but the link doesn't work. If further elaboration on the questions is of help, or if my understanding is flawed, please tell. You're also welcome to point me to resources dealing with these topics. I couldn't find anything on these questions though.
 
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