BJT Homework Help: Troubleshooting Results

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SUMMARY

The forum discussion centers on troubleshooting BJT (Bipolar Junction Transistor) lab results, specifically regarding the collector current (I(c)), base current (I(b)), and emitter current (I(e)). Users express confusion over the effects of resistor combinations R1 and R2 on the transistor's operating region, noting that R1=10k and R2=10k yields a small DC gain, while R1=10k and R2=1k results in a negative I(b), suggesting cutoff mode. The discussion also highlights the importance of accurately calculating I(b) using a more precise method when I(E) is close to I(C).

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  • Research the accurate method for calculating base current (I(b)) in BJT circuits
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Electronics students, hobbyists working with BJTs, and engineers troubleshooting transistor circuits will benefit from this discussion.

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This is the result from a lab,but I am not sure the results are correct.
Also,when I try to find I(c) , I(b) and I(e),by measured V(RC) and V(RE),I find the results strange.
I guess the combination of R1=10k and R2=10k is under linear region,but the dc gain is so small.
For combination of R1=10k and R2=1k,Idon't know why the I(b) is negative.Is it the cut off mode?
And for combination of R1=1k and R2=10k,it should be in saturation?
I guess R2 is like a battery so current I(b) flow ,but how about R1??
 

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You calculated IB using IE - IC. This can be inaccurate when IE is close in value to IC.
There is another way you can determine the value of IB in each test situation, it's a more accurate method, too.

What is this second method I speak of?
 

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