Determine input voltage given resistances

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Discussion Overview

The discussion revolves around calculating the expected input voltage for a CMOS gate given different sets of resistances. Participants explore the implications of infinite resistance and apply the voltage divider rule to derive values for specific resistor combinations.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant questions whether the input voltage would be 0V when R2 is infinite, expressing confusion about the effect of the CMOS gate's infinite input resistance.
  • Another participant corrects the initial voltage divider equation, stating that the input voltage is developed across R2, not R1.
  • A later reply suggests that with R1 at 1K and R2 at infinity, the input voltage would be 5V, indicating a reevaluation of the initial assumption.
  • For R1=1K and R2=10K, one participant calculates v1 as 4.545V using the voltage divider rule, confirming the approach taken in the earlier posts.

Areas of Agreement / Disagreement

Participants appear to agree on the application of the voltage divider rule for finite resistances, but there is some uncertainty regarding the implications of infinite resistance on the input voltage.

Contextual Notes

Participants have not fully resolved the implications of infinite resistance on the input voltage, and there may be assumptions about the behavior of the CMOS gate that are not explicitly stated.

orangeincup
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Homework Statement


[/B]
Calculate the expected input voltage for each set of resistances below. For the CMOS gate, assume the input resist of the gate is infinite.

Homework Equations


i=v/R
Voltage divider rule v*R1/(R1+R2)=v1

The Attempt at a Solution


1)For R1=1K and R2=infinity, would V simply be 0 since the resistance is infinity? I'm mostly confused with how the CMOS gate and the infinity resistance will effect the voltage.

2)For R1=1k and R2=10K
v1=5V*1K/(1K+10K)= 0.45V?

I assume for all the rest, the values with infinity I'd calculate as in step 1, and the values with two specific numbers I'd calculate as I would in step 2?
 

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Check your voltage divider equation: The input voltage is developed across R2, not R1.

orangeincup said:
1)For R1=1K and R2=infinity, would V simply be 0 since the resistance is infinity? I'm mostly confused with how the CMOS gate and the infinity resistance will effect the voltage.
Redraw the input circuit without R2 (an infinite resistance is equivalent to an open circuit):

Fig1.png

What's the input voltage?
 
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Oops,

1)The input voltage would just be 5V then wouldn't it?

2) v1=5V*10K/(1K+10K)=4.545V?
 
orangeincup said:
Oops,

1)The input voltage would just be 5V then wouldn't it?

2) v1=5V*10K/(1K+10K)=4.545V?

Looking good!
 
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