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The entropy of a black hole is S = k_{B}(4∏GM^{2})/(hbar c)

S=Q/T

T= Q/S

T = Q (hbar c)/ (4∏GM^{2}k_{B})

The temperature derived from hawking radiation is:

T = c^{3}hbar/ (8 pi G M k_{B})

Which implies Q = (1/2)M c^{2}

Is this true?

I have found online that the heat should equal to the mass-energy of the black hole,

Mc^{2}

But it was not explained,

Is it correct that Q = (1/2)M c^{2}?

Thanks

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# Black hole temperature derived from entropy (heat from black hole?)

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