- #1

- 61

- 3

The entropy of a black hole is S = k

_{B}(4∏GM

^{2})/(hbar c)

S=Q/T

T= Q/S

T = Q (hbar c)/ (4∏GM

^{2}k

_{B})

The temperature derived from hawking radiation is:

T = c

^{3}hbar/ (8 pi G M k

_{B})

Which implies Q = (1/2)M c

^{2}

Is this true?

I have found online that the heat should equal to the mass-energy of the black hole,

Mc

^{2}

But it was not explained,

Is it correct that Q = (1/2)M c

^{2}?

Thanks