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## Main Question or Discussion Point

Hey,

The entropy of a black hole is S = k

S=Q/T

T= Q/S

T = Q (hbar c)/ (4∏GM

The temperature derived from hawking radiation is:

T = c

Which implies Q = (1/2)M c

Is this true?

I have found online that the heat should equal to the mass-energy of the black hole,

Mc

But it was not explained,

Is it correct that Q = (1/2)M c

Thanks

The entropy of a black hole is S = k

_{B}(4∏GM^{2})/(hbar c)S=Q/T

T= Q/S

T = Q (hbar c)/ (4∏GM

^{2}k_{B})The temperature derived from hawking radiation is:

T = c

^{3}hbar/ (8 pi G M k_{B})Which implies Q = (1/2)M c

^{2}Is this true?

I have found online that the heat should equal to the mass-energy of the black hole,

Mc

^{2}But it was not explained,

Is it correct that Q = (1/2)M c

^{2}?Thanks