dauto said:
The white hole and the black hole are not really two separate regions of the spacetime. They are actually two separate sets of geodesics within the same region of the space time.
No, this is not correct. They are two separate regions of spacetime. The easiest way to see that is to look at a Kruskal diagram, such as the one on the Wikipedia page on Kruskal coordinates:
http://en.wikipedia.org/wiki/Kruskal–Szekeres_coordinates
The black hole is the region marked "II", and the white hole is the region marked "IV". They are not the same.
dauto said:
All the geodesics leading to the hole behave as one would expect a B-hole to behave while all the geodesics leaving the hole behave as one would expect a W-hole to behave.
This doesn't even make sense. Geodesics are individual curves, not regions of spacetime. A region of spacetime can be covered by sets of geodesics, but for any given region, there will be many sets of geodesics that cover it, so you can't equate regions of spacetime with sets of geodesics either.
Also, as I said above, "the hole" is not one region, it's two. Furthermore, there are geodesics that pass through both regions: they leave the white hole (region IV in the diagram), travel through regions I or III, and enter the black hole (region II). So even to the extent it makes sense to compare the "behavior" of geodesics to the "behavior" of a region of spacetime, you can't equate the behavior of geodesics with the behavior of either the black hole or the white hole, since the two holes "behave" differently but the same geodesics can pass through both.
dauto said:
The B-hole and the W-hole are actually intertwined with each other
I'm not sure what you mean by this, but I don't see anything in the math or the physics that corresponds to it.
dauto said:
The point of my previous post is that in the real world if you extend the W-hole geodesics backward in time
Backward in time to where? If you mean taking a geodesic in region I and extending it backward until you reach a portion within region IV, yes, you can do that, but if that's what you mean, then this...
dauto said:
you may never reach the horizon because it may reach a point in time before the horizon formed.
...is false, because there is no point in time before the white hole horizon formed (the WH horizon is different from the BH horizon--that's obvious from the Kruskal diagram).
If, OTOH, you mean taking geodesics in region I and extending them backward in time into the black hole region (region II), that's impossible; there are no such geodesics in the static, maximally extended spacetime.
If you mean taking geodesics in a *different* spacetime, one containing an object that collapses to form a black hole, then yes, you can find geodesics that, if extended backward in time, will reach a time before the black hole formed. But there is no white hole region in this spacetime, so there are no such things as geodesics exiting the white hole.
dauto said:
Hawking radiation exits the hole following these W-geodesics I'm talking about
No, it doesn't. A spacetime with an evaporating black hole is *different* from the one in the Kruskal diagram; it's not static, and it has no white hole region so there are no "white hole geodesics" in this spacetime, just as there aren't in the classical spacetime where an object collapses to form a static (non-evaporating) black hole.
Also, even if the black hole evaporates, that doesn't mean Hawking radiation "exits" the hole. Hawking radiation is formed just outside the event horizon, not within it. The event horizon is a global surface; it's the boundary of the region of spacetime from which light can't escape. Hawking radiation escapes, therefore it does not come from within the event horizon. (Another way of putting this is that an evaporating black hole's event horizon works differently from the horizon of a non-evaporating black hole, because the latter is static and the former is not.)