Blackbody Radiation and Emissivity Explained

AI Thread Summary
Blackbody radiation and emissivity are explained through the behavior of a deep cave, which appears black due to minimal reflection but emits thermal infrared (IR) energy. This emitted energy contains a complete spectrum of IR wavelengths, peaking in the infrared range, because the cave's walls absorb and re-emit all incoming light. The intensity at each wavelength aligns with the predictions of the blackbody radiation curve, indicating maximum possible intensity for that temperature. The cave behaves like a perfect blackbody since incoming light is absorbed rather than reflected, allowing for efficient emission of thermal energy. Overall, the principles of absorption and emission are interconnected, reinforcing the characteristics of blackbody radiation.
Wannabeagenius
Messages
90
Reaction score
0
Hi All,

I'm reading about blackbody radiation and emissivity and I came upon the following statement

"Imagine looking into a small opening of a deep cave. In the visible wavelengths, the opening looks black because the light that enters the cave is not easily reflected back out. However, the cave glows with emitted thermal IR energy. This energy emerges as a complete spectrum of all wavelengths of IR light. The radiance at each infrared wavelength is the maximum amount possible for a given temperature."

Why does the IR energy that emerges contain the complete spectrum of all wavelengths of IR light and why is the intensity at each wavelength the maximum possible? Why does it behave like a perfect blackbody?

Thanks,
Bob
 
Science news on Phys.org
Wannabeagenius said:
Why does the IR energy that emerges contain the complete spectrum of all wavelengths of IR light
Classically it actually contains all wavelengths of all light - it just peaks in the IR

and why is the intensity at each wavelength the maximum possible?
Slightly odd wording - the intensity at each wavelength if it's a blackbody is exactly what the blackbody curve predicts it should be

Why does it behave like a perfect blackbody?
If no outside light is reflected back out without being absorbed by the walls and any light you do see has been emitted by the walls then you get a pretty good blackbody.
 
light entering the cavity bounced back and forth till its almost completely absorbed

emission is just the reverse of absorption
 
Back
Top