Block floating in water - Oil is added

AI Thread Summary
A block of wood initially floats with 75% submerged in water before oil is added. The density of the wood can be calculated using the water's density of 1000 kg/m³. After pouring oil with a density of 715 kg/m³ on top of the water, the buoyant forces from both the water and oil need to be considered. Archimedes' principle and Newton's second law are applied to determine the new fraction of the block submerged. The solution involves calculating the combined buoyant force acting on the block when both fluids are present.
emenos
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Homework Statement


A block of wood floats on water. A layer of oil is now poured on top of the water to a depth that more than covers the block.If 75% of the wood is submerged in water before the oil is added, find the fraction submerged when oil with a density of 715 kg/m3 covers the block. (Do not neglect the buoyant force of air before the oil is added.)



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The Attempt at a Solution

 
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Hey emenos,
The fraction of the block floating initially is given. Get the density of the block from this assuming Dwater=1000kg/m^3. Once you get the density use archimedes principle and Newton's 2nd law to get the required fraction.
 
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