Block on Inclined Plane: The Effects of a Fixed vs. Unfixed Surface

AI Thread Summary
The discussion centers on the dynamics of a block sliding down an inclined plane, considering the effects of a fixed versus unfixed surface. It emphasizes that the inclined plane exerts a force on the block, and according to Newton's third law, the block exerts an equal force back on the plane. If the inclined plane is not fixed, the movement of the plane will depend on the forces acting on it, including the normal force and the mass of both the block and the plane. The participants suggest using free body diagrams to analyze the forces and predict the direction of movement. Overall, the conversation highlights the importance of understanding the interaction between the block and the inclined plane in both fixed and unfixed scenarios.
konichiwa2x
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Hi,
I recently did a problem in which a block of definite mass was placed on the top of a inclined plane which was inclined at some angle with the horizontal. The block starts to slide down. What would happen if the inclined plane was not fixed?
 
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konichiwa2x said:
Hi,
I recently did a problem in which a block of definite mass was placed on the top of a inclined plane which was inclined at some angle with the horizontal. The block starts to slide down. What would happen if the inclined plane was not fixed?
What do yo think would happen?
 
well I think there won't be any effect i.e, it would be the same as if it was fixed. is that right?
 
No. Answer this question: Does the inclined plane exert a force on the block?

Then consider Newton's 3rd law.
 
The movement(s) will depend on the mass of the block and plane, and the coefficient of friction between block/plane and plane/floor.

Imagine what would happen if you had a 50 lb block of ice on a 10 lb 45 degree metal plane on a sheet of ice.
 
No. Answer this question: Does the inclined plane exert a force on the block?

Then consider Newton's 3rd law.

yes , mgcos\theta if \theta is the inclination of the inclined planed with respect to the horizontal. So that means the block also exerts a force equal in magnitude on the inc. plane. I think if the magnitude of this force is large enough, the inclined plane will move . But I am not sure in which direction. Is this correct?
 
konichiwa2x said:
yes , mgcos\theta if \theta is the inclination of the inclined planed with respect to the horizontal. So that means the block also exerts a force equal in magnitude on the inc. plane. I think if the magnitude of this force is large enough, the inclined plane will move . But I am not sure in which direction. Is this correct?
Yes, this is correct. Try drawing a free body diagram and examine the forces. You may also wish to note that conservation of momentum applies here.
 
konichiwa2x said:
yes , mgcos\theta if \theta is the inclination of the inclined planed with respect to the horizontal.
Careful. The force that the incline plane exerts on the block--the normal force--will only equal mg\cos\theta if the plane does not accelerate.
So that means the block also exerts a force equal in magnitude on the inc. plane.
Yes, that is exactly the point.
I think if the magnitude of this force is large enough, the inclined plane will move . But I am not sure in which direction. Is this correct?
Yes. A simple case to analyze is when the inclined plane slides without friction.

The direction that the inclined plane will move is easy to determine. The only horizontal force on the plane is the normal force exerted by the block on the plane. If you draw a diagram showing the forces acting (as Hoot suggests) you will quickly see which way that force acts.
 
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