Boltzmann Distribution with two gasses

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Discussion Overview

The discussion revolves around the Boltzmann distribution in the context of a mixture of two gases with significantly different molecular weights, specifically hydrogen and xenon. Participants explore the implications of this mixture on average momentum, velocity, and energy, considering both theoretical and statistical aspects.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants question whether the gases have equal average momentum or average energy, considering the differences in molecular weights.
  • One participant asserts that at equilibrium, both gases will have the same mean kinetic energy of translation, but their momentum will differ due to their velocities.
  • Another participant notes that the Maxwell distribution curves for the kinetic energies of translation will differ between the two gases, with hydrogen having a lower and broader curve.
  • It is suggested that in a mixture, each gas can be treated independently, and combined statistics can be derived by summing individual statistics.
  • One participant clarifies that if considering momentum in terms of absolute value, the gases will not have the same average absolute momentum, but they will have the same average energy per particle.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between average momentum and energy in the context of the two gases. There is no consensus on whether the gases have equal average momentum or energy, and the discussion remains unresolved.

Contextual Notes

Participants highlight the importance of distinguishing between average momentum and absolute value of momentum, as well as the implications of molecular weight on kinetic energy distributions. The discussion does not resolve the assumptions regarding the treatment of gases in statistical mechanics.

edpell
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What is the Boltzmann distribution look like if we have a mix of two gasses with very different molecular weights? Say hydrogen at 2 amu and xenon at 132 amu. Do they have equal average momentum and hence the hydrogen has an average velocity 66 times the velocity of the xenon and an energy .5*m*v^2 that is 66 times higher than the xenon? Or do they have equal average energy? But shouldn't they both have just .5*kT of energy per degree of freedom?
 
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edpell said:
What is the Boltzmann distribution look like if we have a mix of two gasses with very different molecular weights? Say hydrogen at 2 amu and xenon at 132 amu. Do they have equal average momentum and hence the hydrogen has an average velocity 66 times the velocity of the xenon and an energy .5*m*v^2 that is 66 times higher than the xenon? Or do they have equal average energy? But shouldn't they both have just .5*kT of energy per degree of freedom?

Since the two gases are mixed, at equilibrium they will have the same temperature and hence the same mean kinetic energy of translation. They will not have the same momentum. Molecular momentum is a function of the molecular velocity, but energy of translation is a function of the means of the squares of the velocities. The Maxwell distribution curves of their respective kinetic energies of translation will be different as well. The curve for hydrogen will be lower and broader. The mean total KE per molecule will be 3/2 kT for each gas.

In short, the KE means will be the same, the distributions will be different.
 
The Boltzmann distribution describes a statistic (mean speed) in the microcanonical ensemble. As such, particles of different kinds are non-interacting so in a mixture of two gasses, each species can be treated independently.

If you want a combined statistic for the entire gas, just add up the 2 statistics in the end using the appropriate mathematics.
 
edpell said:
What is the Boltzmann distribution look like if we have a mix of two gasses with very different molecular weights? Say hydrogen at 2 amu and xenon at 132 amu. Do they have equal average momentum and hence the hydrogen has an average velocity 66 times the velocity of the xenon and an energy .5*m*v^2 that is 66 times higher than the xenon? Or do they have equal average energy? But shouldn't they both have just .5*kT of energy per degree of freedom?

If you really mean momentum, and not absolute value of momentum, then they will have the same average momentum per particle, which will be zero. Since the absolute value of momentum is not a conserved quantity, the gases will not have the same average absolute value of momentum. Energy is conserved, so they will have the same average energy per particle.
 

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