Boron esters and oxygen removal

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The discussion centers on the process of removing oxygen from boron powders by milling them in methanol. It is suggested that boron oxide (B2O3) may react with methanol to form boron esters, which could volatilize during the evaporation of the milling solvent under reduced pressure. However, it is noted that significant ester formation is unlikely without an acid catalyst, such as sulfuric acid. The primary ester mentioned is trimethyl borate, which has a boiling point of 69°C at atmospheric pressure. The conversation emphasizes the importance of understanding the chemical reactions involved and the conditions necessary for effective milling and ester formation.
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I would like to remove oxygen from boron powers by milling in milling the starting powders in an alcohol, specifically, methanol. I've been told B2O3 reacts with the methanol to produce boron esters which volatilise during evaporation of the milling solvent under a reduced pressure. Is this true?
How can this be done
 
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Take a look at this thread: https://www.physicsforums.com/showthread.php?t=93439

Although in your case your dealing with boron oxide, I do not think that the mechanism would be much different. You should not get much ester formation without an acid catalyst like sulfuric acid. The primary ester in question is trimethyl borate which boils at 69C at atmospheric pressure.
 
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