Bounds for non-linear recursive sequence

burritoloco
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Homework Statement



We are given the real sequence x_n+1 = (x_n)^2 - 100 + sin(n), some x_0

Prove that if the sequence is bounded with positive numbers, then necessarily
10 <= x_n <= 11 for all n>=0.

Homework Equations





The Attempt at a Solution


I tried induction and it didn't work. Not sure what's the way to go. Thanks for the help!
 
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You could prove the following: if there exist an n such that xn<10 of xn>11, then the sequence becomes unbounded or negative. Try a few examples first!
 
Worked perfectly. Thanks a lot!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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