Box hanging from a rope, need to know the force.

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Homework Help Overview

The discussion revolves around a physics problem involving a 23 kg box hanging from a rope, focusing on the tension in the rope under various conditions of motion, including rest, constant velocity, and acceleration.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the tension in the rope under different scenarios, questioning how to approach parts b), c), and d) after initially solving part a). Some participants discuss the concept of equilibrium and the implications of constant velocity versus acceleration.

Discussion Status

Participants have engaged in a productive exchange, with one member expressing initial confusion but later clarifying their understanding of the relationship between force and acceleration. There is acknowledgment of the need to apply Newton's second law for the latter parts of the problem.

Contextual Notes

Participants are navigating the complexities of forces acting on the box, including gravitational force and tension, while also addressing assumptions related to motion and acceleration.

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A 23 kg box hangs from a rope. What is the tension in the rope if the following are true?

a)The box is at rest?
b)The box moves up at a steady 5.0 m/s?
c)The box has Vy = 5.0 m/s and is speeding up at 5.0 m/s^2?
d)The box has Vy = 5.0 m/s and is slowing down at 5.0 m/s^2


I have gotten a) = 225.4N. Because acceleration is 0. I do not know how to go about solving the other three parts though.

I know the force of gravity is acting on the box in addition to the tension force.

For b):
Since velocity is constant, I would think that the forces would be in equilibrium. But apparently I am wrong. I really have no idea how to solve this.

Any help at all would be appreciated.
 
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I figured it out. Now I feel stupid. Since acceleration is 0 (constant velocity), there would be no change in the force. So for b) the answer would still be 225.4N.
 
This is good, now try 'c' and 'd' using Newtons 2nd law. Welcome to PF!
 
Thanks.

Yeah, sorry I never replied back last night. But I did get the right answers. As soon as I figured out what was going on, everything just clicked.

What I was doing wrong for c and d was that I wasn't accounting for the the change in force. I just found the force with those particular amounts of acceleration.
 

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