Boxes, cables, and girders (torque and equilibirum problem)

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A 75 kg box is placed 2.5 m from the wall on a 10 m steel beam weighing 150 kg, supported by a cable at a 60-degree angle. The tension in the cable has been calculated to be approximately 14321.475 N, but further analysis is needed to determine the force exerted by the wall on the beam. The discussion emphasizes using the principle that the sum of moments about the wall attachment point must equal zero to solve the problem. Participants encourage showing work to facilitate further assistance. The conversation highlights the complexities of torque and equilibrium in this scenario.
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Usually I'm pretty good with torque and such but this one had me.
A box of mass 75 kg is put on a 10-m long steel beam of mass 150 kg and is connected to the wall and supported by a steel cable. The box is located 2.5 m from the wall and the cable makes 60o angle with the beam. What are the magnitude and the direction of the force exerted by the wall on the beam?

Homework Equations


Torque=Radius x Force, upwards/clockwise torque=downwards/counterclockwise torque, weight=mass x gravity

The Attempt at a Solution


I was able to find the tension in the cable, if that helps (14321.475N), but otherwise I'm clueless.
 
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Kind of odd using a 10 m long beam to support a box only 2.5 m away from the wall. Or have I misunderstood?

The usual approach is to write that the sum of the moments about a point (in this case the point where the beam attaches to the wall) is zero. I can't go much further until you give it a try and show your work here.
 
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