Breeding Ratio of thorium fuel cycle

  • Thread starter Thread starter bevan100
  • Start date Start date
  • Tags Tags
    Cycle Fuel Ratio
bevan100
Messages
1
Reaction score
0

Homework Statement


A breeder reactor is designed to work on a thorium fuel cycle. If the reactor generates a constant thermal power of 2.5GW and a production rate of 233U is 52kg per year. Find the breeding Ratio

[You may assume the capture to fission ratio of 233U is 0.09 and the energy released per fission is 197.9Mev.]

Homework Equations


Breeding Ratio= number of fissile nuclei produced/ number of fissile nuclei consumed

The Attempt at a Solution


I really don't know how to go about solving this problem.
I would assume that the capture to fission ratio is important.

The fission of one atom of U-233 generates 197.9 MeV = 3.171 × 10−11 J, i.e. 19.09 TJ/mol = 81.95 TJ/kg.
Then multiply by 0.91 and calculate the energy from fission of 52kg.

81.95 TJ/kg x 52kg x 0.91=3.88x1015J per year

Also reactor produces 2.5GW so I can see this is also really important but get the feeling I am missing something simple as this is the 1st question on a past paper.

Any help really appreciated

Thanks
Lewis
 
Last edited:
Physics news on Phys.org
ha... I am stuck too lewis i swear this wasn't in his notes...

rate of production of new fuel = G w P = 52kg

G = C - 1

where C is the breeding ratio...

strugling to find w (think its to do with the 200 MeV) but i think its simpler than ur calculations
 
Last edited:
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top