Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Breit Wigner for photon intermediates

  1. May 21, 2012 #1
    Hey!

    I'm hoping someone can help me understand a basic problem I'm having with understanding the BW formula:

    [tex]
    \sigma(i,j) = \frac{\pi}{k^2} \frac{\Gamma_i \Gamma_j}{(E - E_0)^2 + \Gamma}
    [/tex]

    In this, [itex]E_0[/itex] is the "characteristic rest mass energy of the resonance." I thought this meant the rest mass of the intermediate particle for the resonance, but in the case of a photon how does this work?

    Then I tried to consider the products, but surely the energy of the final system, and therefore it's rest mass, depends on the energy of the incident particles?

    The specific reaction I'm trying to understand is [itex] e^- + e^+ \rightarrow \gamma \rightarrow \mu^- + \mu^+ [/itex]


    Thanks for any help!
     
  2. jcsd
  3. May 22, 2012 #2

    Bill_K

    User Avatar
    Science Advisor

    What's wrong with the obvious, E0 = 0?
     
  4. May 22, 2012 #3

    Vanadium 50

    User Avatar
    Staff Emeritus
    Science Advisor
    Education Advisor

    The Breit-Wigner is not appropriate for that reaction. It would be appropriate if you were going through a massive resonance, like a phi.
     
  5. May 22, 2012 #4
    Gotcha. Turns out that the resonances I was looking at are due to [itex]b\bar{b}^\star = \Upsilon^\star [/itex] intermediates that decay to [itex] \Upsilon[/itex]s. For anyone else who stumbles on this, these are the resonances at ~10GeV.
     
  6. May 23, 2012 #5

    Bill_K

    User Avatar
    Science Advisor

    Well you may be seeing another resonance, but I still think the Breit-Wigner form (or a limiting case of it) is entirely appropriate for a reaction like this. I'm Looking at Halzen and Martin, who analyze e+ e- → μ+ μ-, specifically for the interference effect caused by neutral currents. That is, the intermediate particle can either be γ or Z. They find the invariant matrix elements (ignoring nonessential factors)

    Mγ = e2/s
    MZ = g2/(s - MZ2 + iMZΓZ)

    where s is the Mandelstam s. The latter is clearly Breit-Wigner, and the former a limiting case of it.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Breit Wigner for photon intermediates
  1. Breit-Wigner formula (Replies: 6)

  2. Breit-Wigner Formula (Replies: 1)

  3. Breit Wigner Formula (Replies: 7)

Loading...