Bridge rectifier and symmetric power supply

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anonymoussome
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Could some one explain how a bridge rectifier works with a diagram and its mathematics?


Also please explain how a center tap transformer and a bridge rectifier are used to provide a symmetric power supply.
I have the Ckt Diagram for that but I cannot understand its working.

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thanks in advance!
 
The normal bridge works as shown in the attached diagram. Red diodes are conducting. Just follow the arrows and look at the polarity.
The capacitor will charge up to 1.414 times the full secondary voltage.

Two bridge rectifier schematics fed from transformer T1 with Vac input: top shows a diode bridge D1-D4 with the V+ output and GND, highlighted pink conducting diodes; bottom shows the same bridge with red conducting diodes and polarity signs marked.


The Symmetric one gives negative and positive voltages.
If you look at it as two full wave rectifiers, it will make more sense.

See attached diagram.

Each capacitor will charge up to 1.414 times half the transformer secondary voltage

Two circuit schematics of rectifiers fed from a transformer T1 with Vac input: the top is a full-wave bridge with diodes D1-D4 and capacitor C2 giving V+ and GND; the bottom is a split-supply rectifier with capacitor C4 giving GND and V-.
 
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