Bullet in a block hitting a spring

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preluderacer
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Homework Statement



An 8-g bullet is shot into a 4.0-kg block, at rest on a frictionless horizontal surface. The bullet remains lodged in the block. The block moves into a spring and compresses it by 5.0 cm. The force constant of the spring is 2200 N/m. In the figure, the initial velocity of the bullet is closest to:


The Attempt at a Solution



what I did was set (mbullet+mblock)vblock=1/2(k)x^2 I solved the the velocity of the block and got 0.686 m/s. Then I set mbullet(v)bullet=(m1+m2)vblock and solved for the vbullet and got 343N. This answer doesn't seem quite right. What am I doing wrong?
 
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preluderacer said:
what I did was set (mbullet+mblock)vblock=1/2(k)x^2 I solved the the velocity of the block and got 0.686 m/s.

The left-hand side of your equation is momentum, the right-hand side is energy. They can not be equal.

ehild
 
i think i got it 1/2(m+M)v^2=1/2(k)(x)^2
 
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