- #1
Sirsh
- 267
- 10
I have a hypothetical scenario I'd like to try understand, and I cannot find anything of the sort online nor in the forums.
If I have a balloon of 1 m3 filled with oil, of a density of 850 kg/m3. Now I place this balloon in a body of water and tether it to a fixed point, how can I find the buoyancy force of this balloon that would 'pull' the tether?
Is this purely an application of Archimedes' principle? Because if that is the case then obviously the force that is created by the balloon of oil is equal to 1 m3 of water that is being displaced. But this does not account for the fact that the oil will have the tendency to rise to the top of the body of water which in itself will cause additional force to act on the tether. Or is the wrong way to think about this problem?
Also, would the depth of water cause additional exertion of force, say if it was 10m below the surface vs. 100m as we know that there is a pressure differential due to increasing weight of the body of water above the object.
Any help is appreciated.
If I have a balloon of 1 m3 filled with oil, of a density of 850 kg/m3. Now I place this balloon in a body of water and tether it to a fixed point, how can I find the buoyancy force of this balloon that would 'pull' the tether?
Is this purely an application of Archimedes' principle? Because if that is the case then obviously the force that is created by the balloon of oil is equal to 1 m3 of water that is being displaced. But this does not account for the fact that the oil will have the tendency to rise to the top of the body of water which in itself will cause additional force to act on the tether. Or is the wrong way to think about this problem?
Also, would the depth of water cause additional exertion of force, say if it was 10m below the surface vs. 100m as we know that there is a pressure differential due to increasing weight of the body of water above the object.
Any help is appreciated.