Buoyant Force and Displacement Volume of a Boat in Lake Superior

AI Thread Summary
The discussion centers on calculating the buoyant force and the volume of water displaced by a boat with a total mass of 15,450 kg in Lake Superior. The buoyant force is calculated using the formula Fb = mg, resulting in 154,500 N when using g = 10 m/s². However, the volume of displaced water was incorrectly calculated as 154,500 m³, which is too large. To find the correct volume, one must consider the density of water, which is approximately 1,000 kg/m³. Ultimately, the volume of displaced water corresponds to the mass of the boat, requiring proper conversion and understanding of density.
disneygirl828
Messages
6
Reaction score
0

Homework Statement


A boat full of people lazily drifts along in Lake Superior. The boat has a mass, including people of 15,450kg.
A. What is the buoyant force?

B. What is the volume of the displaced liquid in cubic meters?




The Attempt at a Solution


A. Fb=mg
Fb=?
m=15,450kg
g= 10m/s
(15450kg)(10m/s)
=154500kg*m/s^2
B.
=154500m^3
 
Physics news on Phys.org
disneygirl828 said:

Homework Statement


A boat full of people lazily drifts along in Lake Superior. The boat has a mass, including people of 15,450kg.
A. What is the buoyant force?

B. What is the volume of the displaced liquid in cubic meters?




The Attempt at a Solution


A. Fb=mg
Fb=?
m=15,450kg
g= 10m/s
(15450kg)(10m/s)
=154500kg*m/s^2
B.
=154500m^3

While "154500kg*m/s^2" is technically correct, it is usual practice to convert the "kg*m/s^2" units to its well-known designation "N" for Newtons, the unit of force.

The displaced water should be equivalent in weight to the weight of the boat. Your value for the volume of displaced water is too large. What is the density of water in kg/m3?
 
gneill said:
While "154500kg*m/s^2" is technically correct, it is usual practice to convert the "kg*m/s^2" units to its well-known designation "N" for Newtons, the unit of force.

The displaced water should be equivalent in weight to the weight of the boat. Your value for the volume of displaced water is too large. What is the density of water in kg/m3?
so the volume of the displaced water would be 15450kg? How do you convert kg*m/s^2 to Newtons?
 
disneygirl828 said:
so the volume of the displaced water would be 15450kg? How do you convert kg*m/s^2 to Newtons?

The volume of the displaced water would be that volume of water which has a mass of 15450kg. To find that volume you will need to know the density of water (kg/m3).

The Newton is defined to be 1 kg*m/s2.
 
Thank you SO much :)
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top