By how much does the speed change each second?

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The discussion revolves around calculating the change in speed of a vehicle with an acceleration of 3 km/h². Participants express confusion about the relevant equations for speed and acceleration, with one attempting to use incorrect calculations. Clarifications are provided regarding the definitions of velocity and displacement, emphasizing the need for understanding resultant displacement in motion problems. The conversation highlights the challenge of connecting theoretical knowledge with practical homework problems. Overall, the participants seek guidance on applying the correct formulas to solve their physics questions effectively.
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Homework Statement


A vehicle moves in a straight line with an
acceleration of 3 km/h2.
By how much does the speed change each
second?
Answer in units of km/h.


Homework Equations


Not sure


The Attempt at a Solution


sqrt 3 to get a base answer then divide by 3600
I have also tried doing the problem directly. 3 divided by 36002 . Gives me a large number I am unsure is correct.

But when i don't get it right i start guessing.
 
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Welcome to PF!

Hi kremit! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

What equations do you know relating speed and acceleration? :smile:
 


i have a change in speed over a change in time to equal velocity. I also have an average and instantaneous speed too. I also fixed the ^2 to the correct super script. I think that is what that is called. lol

It's strange though. There is no other figures, that could be why I am stuck.
 
Last edited:
Hi kremit! :smile:

(just got up :zzz: …)
kremit said:
A vehicle moves in a straight line with an
acceleration of 3 km/h2.
By how much does the speed change each
second?
kremit said:
i have a change in speed over a change in time to equal velocity. I also have an average and instantaneous speed too.

No, change in distance over change in time equals velocity (∆x/∆t = v).

ok, that doesn't help here, so …

do you have a similar equation that includes acceleration? :smile:
I also fixed the ^2 to the correct super script. I think that is what that is called. lol


Yeah! Super! :biggrin:
 


Why must this be so hard for me. I don't understand that.

I looked in my book,on the web, and not making sense of what a "resultant displacement" is.

The problem to this is simple.

Guy passes a 241km marker, passes 172km marker, and hits a 148km marker. he then backtracks to the 172km marker. What is the resultant displacement
 
Hi kremit! :smile:

(are you ok on the previous question?)

Displacement means total change in position.

For example, if you go half-way round a circle of radius r, then you have gone a distance (or arc-length) of πr, but your displacement is only 2r.

And if you go all the way round a circle of radius r, then you have gone a distance (or arc-length) of 2πr, but your displacement is zero! :smile:

(and "resultant" always simply means "overall", you take everything into account, and then calculate the displacement :wink:)

So what is the overall displacement in this case?​
 


A change in total position. Wonder why they couldn't say that? :redface:

Guy passes a 241km marker, passes 172km marker, and hits a 148km marker. he then backtracks to the 172km marker

He went the entire distance of

93km from 241km -> 148km
69km from 241km -> 172km
24km from 172km -> 148km

93km - 24km ?
93km + 24km?

I doubt it's that simple, but he traveled the whole distance and came back.

I like how our lab or lecture has nothing to do with our homework. Then must rely on others or tutors to teach me equations. :rolleyes:
 
Hi kremit! :smile:

Where did he start from? The 241 km marker? :confused:

If so, just follow the definition … total displacement is |241 - 172|.
 

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