When we say that the the velocity of light, c, is independent of the velocity of emitter or the observer, does it mean that ..(adsbygoogle = window.adsbygoogle || []).push({});

if we are in an spaceship and measure c with Fizeau arrangement we will obtain the same result, no matter the velocity of the spaceship nor the velocity of the emitter ?

Fizeau experiment : "http://laser.phys.ualberta.ca/~egerton/cðer.htm" [Broken] drawing: Fizeaus method

( and no matter the angle between the Fizeau device and the direction of the incoming light )

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# C independent of observer and emitter

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