C program (string - binary to decimal conversion)

[clook]

here's what i have:

#include<stdio.h>
#include<string.h>
main() {
char string[32];
int sum = 0;
int a = 1;
int i;
printf("Please enter numbers:\n");
gets(string);
for (i=32;i<0;i--)
{
if(string[i] ==1)
{ sum = sum + a;
}
a = a * 2;
printf("The converted string is: %s \n", string[i]);
}

won't compile.. says "compound" statement is missing at the end.

what am i doing wrong?

Homework Equations

The Attempt at a Solution

 

[berkeman]

Count the number of left and right braces {}. You just spaced the one at the end of the main().

 

[yamini]

have you noticed one thing...that 1)in the program you have opened three braces and two closed braces{}, 2)why don't you declare as
int sum=o,a=1,i; 3)why don't you prefer to use getch( ); before the ending brace.

 

[Hurkyl]

2)why don't you declare as
int sum=o,a=1,i;

It's a matter of style. Some prefer not to declare many things on one line, especially if there are initializers or modifiers involved.

3)why don't you prefer to use getch( ); before the ending brace.

(A) There's no reason to wait for a keypress
(B) getch is a nonstandard extension to the C language. You can only use it if you happen to be using a compiler or library that defines it. (Why not use getchar() instead?)

 

[jim mcnamara]

Did your teacher ever mention strtoul() ?