Calculate Angle of Twist for Steel Shaft, 850 lb-in Applied

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SUMMARY

The discussion focuses on calculating the angle of twist for a steel shaft subjected to a torque of 850 lb-in. The governing equation used is θ = (T * L) / (G * J), where J is the polar moment of inertia. The shaft has two flats with a measurement of 1.25 inches across the flats, leading to the need to compute two J values for accurate results. The final angle of twist is determined by the difference between the angles calculated for each section of the shaft.

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  • Understanding of torsion and shear stress in materials
  • Familiarity with the polar moment of inertia (J) calculation
  • Knowledge of the modulus of rigidity (G) for steel
  • Basic algebra for manipulating equations
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1. Homework Statement

Compute angle of twist of one end relative to other if a torque of 850 lb-in is applied uniformly along the length. Shaft has two flats (not just the 1 pictured!) 1.25 " is measurement across flats.


Homework Equations


J = C r^4


The Attempt at a Solution


I had to hand in the page with the question on it recently :(

so, here are the governing equations, need some direction on how to tackle it:

so the value of J is easily computed (table: 0.625" / 0.875" = C of around 0.93 x 0.316 = 0.294)

angle = [(torque)(length)]/[GJ])

so since there are two J values, how is this handled? thanks
 
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I think you will need to split it as two shafts with the same torque value T. So you'd get θ1 using J1 and θ2 using J2.

The relative angle would then be θ21.


I could be wrong though as it's been quite long since I've done these types of things :redface:
 
ok I'll try that

although the answer is very small and would kinda be the same even if you did it wrong. So I need to know
 

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