# Calculate Density of Object: 15N in Air, 13N in Water

• 7starmantis
In summary, an object weighs 15N in air and 13N when submerged in water. Determining the density of the object requires solving for volume and mass, and neglecting the density of air.
7starmantis
An object weighs 15N in air and 13N when submerged in water. determine the density of the object.
Am I setting this up correctly, I'm confused about the two masses.
Volume = W(air) - W(water) / pg
15-13 / (1000)(9.8) = 2.0x10^4
p(density) = m/V
What mass do I use here though, the one in air or water?

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I don't know whether your solution is correct, but I can tell you that mass and weight are not the same thing. The object's mass is the same no matter where it is

How do I go about finding the density? Don't I need to find volume first then use volume in the density equation?

Weight in air is:

m*g - volume of the object* density of the air* g

weight in watter is

m*g - volume of the object* density of water*g

You already solved for the volume now solve for the mas and then apply your density formula.

I'm confused, that still leaves me with two separate values for mass. Which value would I use in the density equation?

How does that leave you with "two separate values for mass"? John Creighto told you to set the two quantities equal and solve for mass. There will only be one solution.

I didn't get that he said to set them equal to each other, but I also don't know the density of the air.

So:
m*g - volume of the object* density of the air* g = m*g - volume of the object* density of water*g

I have everything except density of air.

Generally it is small enough to ignore (it is roughly 1/1000 the density of water )
If you look at the equation it is an additive term so calculate your answer ignoring it and then calculate the answer again using 1.3kg/m^3 and you will see that the difference in the mass of the object is small.

In general you can ignore small terms when they are added/subtracted but yuo need them when they are multiplied/divided - can you see why?

I'm so frustrated by this problem I can't even think straight anymore.
I don't understand what you mean by it being an additive term, isn't it multiplied in the equation? But at this point I can't even figure out how to solve the equation with or without it.

We did a lab like this, but my teacher hasn't returned our lab reports yet and it has all my data in it. I just can't for the life of me understand how to setup the problem.

Not quite set them equal, you are given two differnet weights
m*g - volume of the object* density of the air* g = 15N
m*g - volume of the object* density of water*g = 13N

Lets just look at the equation:
m*g - V*air*g = 15N
m*g - V* water*g = 13N

Since density of air is small then anything multiplied by it is small, so the term V*air*g is small. This is added to the m*g, this is what is meant by an additive term. Adding a small number to a big one doesn't do much so you can ignore it.

m*g = 15N
m*g - V* water*g = 13N

or 15N - V*water*g = 13N, so V*water*g = 2N
You know density of water so can work out the volume.
Once you have the volume and you know it's weight in air you can work out it's density, once again ignoring the density of air.

It's easy to get confused once you start writing the equations, it's important to have a clear picture of what is happening first.
Draw a diagram showing all the forces. And finally do a quick check that the units balance,
V*water*g = 2N is m^3 * kg/m^3 * m/s^2 = kg m/s^2 = N

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Considering you're looking for the density it might be better to use that term in your equations.

Weight in air:

$$V_o (\rho_o-\rho_a)g = 15N$$

Weight in water:

$$V_o(\rho_o - \rho_w)g = 13N$$

Then one has two variables and two simultaneous equations. You can solve for Vo from one of the equations and substitute back into the second to find the final answer. As others have said you can probably ignore the density of air.

So basically since$$\rho$$gv = 2N
Volume = 2N / $$\rho$$g
Volume = 2.0X10^-4

Then the weight in air is 15N / 9.8 = 1.53kg

$$\rho$$ object = m/v
= 1.53kg/2.0X10^-4
= 7650

That make sense? I hope so, cause it does to me... :)

## 1. What is density?

Density is a measure of how much mass is contained in a given volume of a substance. It is calculated by dividing the mass of an object by its volume.

## 2. How do you calculate the density of an object?

The density of an object is calculated by dividing its mass by its volume. The formula for density is: density = mass / volume. This will give you the density in units of mass per unit volume, such as grams per cubic centimeter or kilograms per cubic meter.

## 3. How do you measure the mass of an object?

The mass of an object can be measured using a scale or balance. It is important to make sure the scale is properly calibrated and to take into account the weight of any containers or tools used to hold the object.

## 4. How do you measure the volume of an object?

The volume of an object can be measured in various ways depending on the shape and size of the object. One common method is to use a graduated cylinder or measuring cup to measure the volume of a liquid. For irregularly shaped objects, the volume can be determined by measuring the displacement of water when the object is submerged.

## 5. How does the density of an object change in different mediums?

The density of an object may change depending on the medium it is placed in. In the example given, the density of 15N in air would be different from its density in water. This is because different mediums have different densities. For example, water is more dense than air, so an object will appear to be lighter in water than in air.

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