Calculate Heat loss without k (thermal constant)

[omer10000]

Homework Statement

An 16m by 9.0m house is built on a concrete slab 20cm thick. What is the heat-loss rate through the floor if the interior is at 29°C while the ground is at 19°C?

Given:

Area = 16*9 = 144m^2
DeltaX = 20cm = 0.2m
DeltaT = 29-19 = 10°C

k = not given

H = ?

Homework Equations

Equation (i believe): H = (-k*A*DeltaT)/DeltaX

The Attempt at a Solution

I calculated the heat loss with the above given details but apparently the answer does not depend on the variable k (thermal conductivity).

Anyone got any ideas?

 

[Asim Riaz]

The answer is 5.76 kW/m2.No, the answer does not depend on the thermal conductivity (k). What you need to do is calculate the total heat loss from the floor, which is given by H = (-A*DeltaT)/DeltaX, where A is the area of the floor, DeltaT is the temperature difference between the interior and the ground, and DeltaX is the thickness of the floor. Once you have calculated the total heat loss, you can divide it by the area of the floor to get the heat-loss rate per unit area.